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Data Visualizationmedium
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In a moderately skewed unimodal distribution represented by a histogram, the mode is 42.042.042.0 and the median is 50.050.050.0. If Pearson's mode skewness coefficient is calculated as textSkewness=fractextmean−textmodetextstandarddeviation=0.60\\text{Skewness} = \\frac{\\text{mean} - \\text{mode}}{\\text{standard deviation}} = 0.60textSkewness=fractextmean−textmodetextstandarddeviation=0.60, what must be the value of the mean?