If z=eiαz = e^{i\alpha}z=eiα, find (1−z)2(1−zˉ)2(1 - z)^2(1 - \bar{z})^2(1−z)2(1−zˉ)2.
∣1−z∣4|1 - z|^4∣1−z∣4
∣1−eiα∣4|1 - e^{i\alpha}|^4∣1−eiα∣4
4sin4(α/2)4\sin^4(\alpha/2)4sin4(α/2)
16sin4(α/2)16\sin^4(\alpha/2)16sin4(α/2)