If z=1+i3z = 1 + i\sqrt{3}z=1+i3, express zzz in the form reiθr e^{i\theta}reiθ.
2eiπ/32e^{i\pi/3}2eiπ/3
2(cos(π/3)+isin(π/3))2(\cos(\pi/3) + i\sin(\pi/3))2(cos(π/3)+isin(π/3))
Both a and b
3eiπ/3\sqrt{3} e^{i\pi/3}3eiπ/3