If y1(x)y_1(x)y1(x) and y2(x)y_2(x)y2(x) are two solutions to y′+p(x)y=q(x)y' + p(x)y = q(x)y′+p(x)y=q(x), what can be said about y3(x)=y1(x)−y2(x)y_3(x) = y_1(x) - y_2(x)y3(x)=y1(x)−y2(x)?
y3y_3y3 is a solution to y′+p(x)y=q(x)y' + p(x)y = q(x)y′+p(x)y=q(x)
y3y_3y3 is a solution to y′+p(x)y=0y' + p(x)y = 0y′+p(x)y=0
y3y_3y3 is a constant
y3y_3y3 is a solution to y′+p(x)y=2q(x)y' + p(x)y = 2q(x)y′+p(x)y=2q(x)