If y=ln(x3)y = \ln(x^3)y=ln(x3), find dydx\frac{dy}{dx}dxdy for x>0x > 0x>0.
1x3\frac{1}{x^3}x31
3x3\frac{3}{x^3}x33
1x\frac{1}{x}x1
3x\frac{3}{x}x3