Diophantine Equationseasy
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If (x1,y1)=(3,2)(x_1, y_1) = (3, 2) and (x2,y2)=(17,12)(x_2, y_2) = (17, 12) both satisfy x22y2=1x^2 - 2y^2 = 1, the Brahmagupta-Fibonacci identity produces a new solution using: (x1x2+2y1y2,x1y2+x2y1)(x_1 x_2 + 2y_1 y_2, x_1 y_2 + x_2 y_1). What is the new solution?