If x,y,zx, y, zx,y,z are in a geometric progression and x+y+z=21x+y+z = 21x+y+z=21 and x−1+y−1+z−1=7/12x^{-1} + y^{-1} + z^{-1} = 7/12x−1+y−1+z−1=7/12, what are x,y,zx, y, zx,y,z?
3,6,123, 6, 123,6,12
1,4,161, 4, 161,4,16
2,4,82, 4, 82,4,8
3,9,273, 9, 273,9,27