If x=6+6+…x = \sqrt{6 + \sqrt{6 + \dots}}x=6+6+…, which quadratic equation does xxx satisfy?
x2+x−6=0x^2 + x - 6 = 0x2+x−6=0
x2−x−6=0x^2 - x - 6 = 0x2−x−6=0
x2−6x+1=0x^2 - 6x + 1 = 0x2−6x+1=0
x2+6x−1=0x^2 + 6x - 1 = 0x2+6x−1=0