If X∼Binomial(n,p)X \sim \text{Binomial}(n, p)X∼Binomial(n,p), what is the value of the ratio P(X=k+1)/P(X=k)P(X=k+1) / P(X=k)P(X=k+1)/P(X=k)?
\frac{(n-k)p}{(k+1)(1-p)}
\frac{(n-k)(1-p)}{(k+1)p}
\frac{(k+1)p}{(n-k)(1-p)}
\frac{np}{k(1-p)}