If X∼Poisson(λ=4)X \sim \text{Poisson}(\lambda = 4)X∼Poisson(λ=4), what is P(X=0)P(X = 0)P(X=0)?
e−4e^{-4}e−4
4e−44e^{-4}4e−4
e4e^4e4
14\frac{1}{4}41