If X∼N(10,16)X \sim N(10, 16)X∼N(10,16), find xxx such that P(X>x)=0.1587P(X > x) = 0.1587P(X>x)=0.1587. (Given Φ(1)≈0.8413\Phi(1) \approx 0.8413Φ(1)≈0.8413 where Φ\PhiΦ is standard normal CDF)
x=12x = 12x=12
x=14x = 14x=14
x=6x = 6x=6
x=18x = 18x=18