If X∼N(10,16)X \sim N(10, 16)X∼N(10,16), find the value of xxx such that P(X>x)=0.1587P(X > x) = 0.1587P(X>x)=0.1587. Given Φ(1)≈0.8413\Phi(1) \approx 0.8413Φ(1)≈0.8413.
x=11x = 11x=11
x=14x = 14x=14
x=18x = 18x=18
x=16x = 16x=16