If the length of a diagonal of a square is a+ba+ba+b, then its area is:
(a+b)2/2(a+b)^2 / 2(a+b)2/2
(a+b)2(a+b)^2(a+b)2
a2+b2a^2+b^2a2+b2
2(a+b)22(a+b)^22(a+b)2