If the function F(x)=∫2x2t3+1 dtF(x) = \int_2^{x^2} \sqrt{t^3 + 1} \, dtF(x)=∫2x2t3+1dt, what is the derivative F′(x)F'(x)F′(x) at x=1x = 1x=1?
2\sqrt{2}2
222\sqrt{2}22
13+1=2\sqrt{1^3+1} = \sqrt{2}13+1=2
213+1=222\sqrt{1^3+1} = 2\sqrt{2}213+1=22