If tan(A)=3\tan(A) = 3tan(A)=3 and tan(B)=4\tan(B) = 4tan(B)=4, find tan(A+B)\tan(A+B)tan(A+B).
−1/11-1/11−1/11
7/117/117/11
11/711/711/7
−7/11-7/11−7/11