If sin(θ)=23\sin(\theta) = \frac{2}{3}sin(θ)=32 and θ\thetaθ is in the first quadrant, what is sin(90∘−θ)\sin(90^\circ - \theta)sin(90∘−θ)?
23\frac{2}{3}32
53\frac{\sqrt{5}}{3}35
13\frac{1}{3}31
52\frac{\sqrt{5}}{2}25