If sinA=1/3\sin A = 1/3sinA=1/3 and cosB=1/4\cos B = 1/4cosB=1/4 (both acute), find sin(A+B)\sin(A+B)sin(A+B).
8+31512\frac{\sqrt{8}+3\sqrt{15}}{12}128+315
8+31515\frac{\sqrt{8}+3\sqrt{15}}{15}158+315
1+1512\frac{1+\sqrt{15}}{12}121+15
8+112\frac{\sqrt{8}+1}{12}128+1