If P(x)=x3−2x2−5x+6P(x) = x^3 - 2x^2 - 5x + 6P(x)=x3−2x2−5x+6 and P(1)=0P(1) = 0P(1)=0, completely factor P(x)P(x)P(x).
(x−1)(x−3)(x+2)(x - 1)(x - 3)(x + 2)(x−1)(x−3)(x+2)
(x−1)(x+3)(x−2)(x - 1)(x + 3)(x - 2)(x−1)(x+3)(x−2)
(x+1)(x−3)(x+2)(x + 1)(x - 3)(x + 2)(x+1)(x−3)(x+2)
(x−1)(x2−x−6)(x - 1)(x^2 - x - 6)(x−1)(x2−x−6)