If P(A∣B)>P(A)P(A|B) > P(A)P(A∣B)>P(A), then which of the following must also be true?
P(B∣A)>P(B)P(B|A) > P(B)P(B∣A)>P(B)
P(B∣A)<P(B)P(B|A) < P(B)P(B∣A)<P(B)
AAA and BBB are independent
P(A∩B)=0P(A \cap B) = 0P(A∩B)=0