If P(A)=xP(A) = xP(A)=x and P(B)=yP(B) = yP(B)=y are independent, what is P(Ac∩Bc)P(A^c \cap B^c)P(Ac∩Bc)?
1−x−y+xy1-x-y+xy1−x−y+xy
1−x−y1-x-y1−x−y
xyxyxy
(1−x)(1−y)(1-x)(1-y)(1−x)(1−y)