If P(A∪B)=0.8P(A \cup B) = 0.8P(A∪B)=0.8, P(A)=0.5P(A) = 0.5P(A)=0.5, and P(B)=0.4P(B) = 0.4P(B)=0.4, what is P(A∩B)P(A \cap B)P(A∩B)?
0.1
0.2
0.3
0.9