If P(A)=0.6P(A) = 0.6P(A)=0.6, P(B)=0.4P(B) = 0.4P(B)=0.4, and P(A∪B)=0.8P(A \cup B) = 0.8P(A∪B)=0.8, what is P(A∩B)P(A \cap B)P(A∩B)?
0.20.20.2
0.240.240.24
0.30.30.3
0.40.40.4