If P(A)=0.6P(A) = 0.6P(A)=0.6 and P(B∣A)=0.5P(B|A) = 0.5P(B∣A)=0.5, then P(A∩B)P(A \cap B)P(A∩B) is:
0.3
0.1
0.83
0.2