If P(A)=0.6P(A) = 0.6P(A)=0.6 and P(B)=0.4P(B) = 0.4P(B)=0.4, and they are mutually exclusive, what is P(A∪B)P(A \cup B)P(A∪B)?
1.0
0.24
0.76
0.4