If P(A)=0.4P(A) = 0.4P(A)=0.4, P(B)=0.3P(B) = 0.3P(B)=0.3, and P(A∪B)=0.58P(A \cup B) = 0.58P(A∪B)=0.58, are they independent?
Yes
No
Impossible to tell
Yes, because 0.4 + 0.3 - 0.58 = 0.12 = 0.4 * 0.3