If P(A)=0.3,P(B)=0.6P(A) = 0.3, P(B) = 0.6P(A)=0.3,P(B)=0.6, and P(A∪B)=0.7P(A \cup B) = 0.7P(A∪B)=0.7, are AAA and BBB independent?
Yes, because P(A)P(B)=P(A∩B)P(A)P(B) = P(A \cap B)P(A)P(B)=P(A∩B)
No, because P(A)P(B)≠P(A∩B)P(A)P(B) \neq P(A \cap B)P(A)P(B)=P(A∩B)
Yes, because P(A∪B)=P(A)+P(B)P(A \cup B) = P(A) + P(B)P(A∪B)=P(A)+P(B)
No, because P(A∪B)≠P(A)+P(B)P(A \cup B) \neq P(A) + P(B)P(A∪B)=P(A)+P(B)