If P(A)=0.3P(A) = 0.3P(A)=0.3, P(B)=0.4P(B) = 0.4P(B)=0.4, and P(A∣B)+P(B∣A)=0.9P(A|B) + P(B|A) = 0.9P(A∣B)+P(B∣A)=0.9, find P(A∩B)P(A \cap B)P(A∩B).
0.12
0.14
0.15
0.18