If nnn is a positive integer, factor n4+4nn^4 + 4nn4+4n using Sophie Germain's identity.
n(n+2)(n2−2n+2)n(n+2)(n^2-2n+2)n(n+2)(n2−2n+2)
n(n3+4)n(n^3+4)n(n3+4)
n(n+1)(n−1)(n+2)n(n+1)(n-1)(n+2)n(n+1)(n−1)(n+2)
(n2+2)2(n^2+2)^2(n2+2)2