If ln(x+y)=ln(x)+ln(y)\ln(x + y) = \ln(x) + \ln(y)ln(x+y)=ln(x)+ln(y), express yyy in terms of xxx.
y=xx−1y = \frac{x}{x-1}y=x−1x
y=x2y = x^2y=x2
y=x−1xy = \frac{x-1}{x}y=xx−1
y=exy = e^xy=ex