If L=lcm(a,b)L = \text{lcm}(a, b)L=lcm(a,b), which statement is always true?
Both aaa and bbb divide LLL
LLL divides both aaa and bbb
L=a⋅bL = a \cdot bL=a⋅b for all choices of a,ba, ba,b
LLL is prime when gcd(a,b)=1\gcd(a, b) = 1gcd(a,b)=1