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Integralseasy
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If ∫02f(x)dx=4\int_0^2 f(x) dx = 4∫02​f(x)dx=4 and ∫25f(x)dx=7\int_2^5 f(x) dx = 7∫25​f(x)dx=7, what is ∫05f(x)dx\int_0^5 f(x) dx∫05​f(x)dx?