If ∫01f(x)dx=3\int_0^1 f(x) dx = 3∫01f(x)dx=3 and ∫01g(x)dx=2\int_0^1 g(x) dx = 2∫01g(x)dx=2, evaluate ∫01(f(x)+g(x))dx\int_0^1 (f(x) + g(x)) dx∫01(f(x)+g(x))dx.
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