If ∫0k2xdx=9\int_0^k 2x dx = 9∫0k2xdx=9, find kkk (assume k>0k > 0k>0).
k=3k = 3k=3
k=9k = 9k=9
k=3k = \sqrt{3}k=3
k=32k = 3\sqrt{2}k=32