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Integrals
easy
0:00.0
If
g
(
x
)
=
∫
1
x
(
t
2
+
2
)
d
t
g(x) = \int_1^x (t^2 + 2) dt
g
(
x
)
=
∫
1
x
(
t
2
+
2
)
d
t
, find
g
′
(
2
)
g'(2)
g
′
(
2
)
.
A
6
B
3
C
2
D
0
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