If gcd(a,c)=1\gcd(a, c) = 1gcd(a,c)=1 and gcd(b,c)=1\gcd(b, c) = 1gcd(b,c)=1, then gcd(ab,c)=?\gcd(ab, c) = ?gcd(ab,c)=?
gcd(a,c)⋅gcd(b,c)=1⋅1=1\gcd(a, c) \cdot \gcd(b, c) = 1 \cdot 1 = 1gcd(a,c)⋅gcd(b,c)=1⋅1=1
111
gcd(a,b)\gcd(a, b)gcd(a,b)
Depends on the specific values of aaa, bbb, ccc