If gcd(a,b)=1\gcd(a, b) = 1gcd(a,b)=1, and a⋅ba \cdot ba⋅b is a perfect square, what must be true about aaa and bbb?
Both aaa and bbb are perfect squares
aaa is a perfect square, bbb is not
a=ba = ba=b
a+ba+ba+b is a perfect square