If f(x,y)=x3−4y2f(x, y) = x^3 - 4y^2f(x,y)=x3−4y2, what is ∂f∂x\frac{\partial f}{\partial x}∂x∂f?
3x2−8y3x^2 - 8y3x2−8y
3x2−4y23x^2 - 4y^23x2−4y2
3x23x^23x2
x3x^3x3