If f(x,y)=x2y3f(x, y) = x^2 y^3f(x,y)=x2y3, what is ∂f∂x\frac{\partial f}{\partial x}∂x∂f?
2xy32xy^32xy3
3x2y23x^2y^23x2y2
2x+3y2x + 3y2x+3y
x2y3x^2 y^3x2y3