If f(x)=x2ekxf(x) = x^2 e^{kx}f(x)=x2ekx, find kkk such that f′′(1)=0f''(1) = 0f′′(1)=0.
k=−2k = -2k=−2
k=−1k = -1k=−1
k=2k = 2k=2
k=1k = 1k=1