If f(x)=x2f(x) = x^2f(x)=x2 and g(x)=x+1g(x) = x+1g(x)=x+1, which is true for (g∘f)(x)(g \circ f)(x)(g∘f)(x)?
(g∘f)(x)=x2+1(g \circ f)(x) = x^2+1(g∘f)(x)=x2+1
(g∘f)(x)=(x+1)2(g \circ f)(x) = (x+1)^2(g∘f)(x)=(x+1)2
(g∘f)(x)=x2+x(g \circ f)(x) = x^2+x(g∘f)(x)=x2+x
(g∘f)(x)=2x2(g \circ f)(x) = 2x^2(g∘f)(x)=2x2