If f(x)=x2f(x) = x^2f(x)=x2 and g(x)=xg(x) = \sqrt{x}g(x)=x, which is true regarding their composition?
(g∘f)(x)=∣x∣(g \circ f)(x) = |x|(g∘f)(x)=∣x∣
(f∘g)(x)=x(f \circ g)(x) = x(f∘g)(x)=x for all x∈Rx \in \mathbb{R}x∈R
(g∘f)(x)=x(g \circ f)(x) = x(g∘f)(x)=x
Both fff and ggg are bijections on R\mathbb{R}R