If f(x)=x2−5f(x) = x^2 - 5f(x)=x2−5, find f(x+1)f(x+1)f(x+1).
x2+2x−4x^2 + 2x - 4x2+2x−4
x2−4x^2 - 4x2−4
x2+2x+1x^2 + 2x + 1x2+2x+1
x2−6x^2 - 6x2−6