If f(x)=∣x−1∣f(x) = |x - 1|f(x)=∣x−1∣ and g(x)=2g(x) = 2g(x)=2, for which xxx is f(x)<g(x)f(x) < g(x)f(x)<g(x)?
−1<x<3-1 < x < 3−1<x<3
x<3x < 3x<3
x>−1x > -1x>−1
0<x<20 < x < 20<x<2