If f(x)=sin(x2)f(x) = \sin(x^2)f(x)=sin(x2), what is f′′(x)f''(x)f′′(x)?
2cos(x2)−4x2sin(x2)2\cos(x^2) - 4x^2\sin(x^2)2cos(x2)−4x2sin(x2)
2cos(x2)−2x2sin(x2)2\cos(x^2) - 2x^2\sin(x^2)2cos(x2)−2x2sin(x2)
−4x2sin(x2)-4x^2\sin(x^2)−4x2sin(x2)
4x2cos(x2)4x^2\cos(x^2)4x2cos(x2)