If f(x)=ln(x2−1)f(x) = \ln(x^2 - 1)f(x)=ln(x2−1) and g(x)=ln(x−1)+ln(x+1)g(x) = \ln(x-1) + \ln(x+1)g(x)=ln(x−1)+ln(x+1), for what set of xxx is f(x)=g(x)f(x) = g(x)f(x)=g(x)?
(1,∞)(1, \infty)(1,∞)
All real xxx
Empty set
(−∞,−1)∪(1,∞)(-\infty, -1) \cup (1, \infty)(−∞,−1)∪(1,∞)