If F(x)=∫2x3t2+1dtF(x) = \int_{2}^{x^3} \sqrt{t^2+1} dtF(x)=∫2x3t2+1dt, what is the derivative F′(x)F'(x)F′(x)?
3x2x6+13x^2\sqrt{x^6+1}3x2x6+1
x6+1\sqrt{x^6+1}x6+1
3x2x2+13x^2\sqrt{x^2+1}3x2x2+1
13x2x6+1\frac{1}{3x^2}\sqrt{x^6+1}3x21x6+1