If f(x)=x−2x+3f(x) = \frac{x-2}{x+3}f(x)=x+3x−2, find f−1(x)f^{-1}(x)f−1(x).
f−1(x)=3x+21−xf^{-1}(x) = \frac{3x+2}{1-x}f−1(x)=1−x3x+2
f−1(x)=3x+2x−1f^{-1}(x) = \frac{3x+2}{x-1}f−1(x)=x−13x+2
f−1(x)=x+3x−2f^{-1}(x) = \frac{x+3}{x-2}f−1(x)=x−2x+3
f−1(x)=−3x−2x−1f^{-1}(x) = \frac{-3x-2}{x-1}f−1(x)=x−1−3x−2