If f(x)=x−1x+1f(x) = \frac{x-1}{x+1}f(x)=x+1x−1, find the nnn-th iterate fn(x)=(f∘f∘⋯∘f)(x)f_n(x) = (f \circ f \circ \dots \circ f)(x)fn(x)=(f∘f∘⋯∘f)(x) for n=2025n=2025n=2025.
x−2025x+2025\frac{x-2025}{x+2025}x+2025x−2025
x−1x+1\frac{x-1}{x+1}x+1x−1
−1/x-1/x−1/x
xxx