If f(x)=2x+3x−1f(x) = \frac{2x+3}{x-1}f(x)=x−12x+3, find f−1(x)f^{-1}(x)f−1(x).
f−1(x)=x+3x−2f^{-1}(x) = \frac{x+3}{x-2}f−1(x)=x−2x+3
f−1(x)=x−3x+2f^{-1}(x) = \frac{x-3}{x+2}f−1(x)=x+2x−3
f−1(x)=x+12x−3f^{-1}(x) = \frac{x+1}{2x-3}f−1(x)=2x−3x+1
f−1(x)=x+32−xf^{-1}(x) = \frac{x+3}{2-x}f−1(x)=2−xx+3