If f(x)=1xf(x) = \frac{1}{x}f(x)=x1, find the value of the finite sum ∑k=1100ak\sum_{k=1}^{100} a_k∑k=1100ak where a1=2a_1 = 2a1=2 and an+1=f(an)a_{n+1} = f(a_n)an+1=f(an).
100
100.5
50.5
51